4(2x-7)-5x=6(x-3)-4

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Solution for 4(2x-7)-5x=6(x-3)-4 equation: 



4(2x-7)-5x=6(x-3)-4

We move all terms to the left:

4(2x-7)-5x-(6(x-3)-4)=0

We add all the numbers together, and all the variables

-5x+4(2x-7)-(6(x-3)-4)=0

We multiply parentheses

-5x+8x-(6(x-3)-4)-28=0



We calculate terms in parentheses: -(6(x-3)-4), so:

6(x-3)-4

We multiply parentheses

6x-18-4

We add all the numbers together, and all the variables

6x-22

Back to the equation:

-(6x-22)



We add all the numbers together, and all the variables

3x-(6x-22)-28=0

We get rid of parentheses

3x-6x+22-28=0

We add all the numbers together, and all the variables

-3x-6=0

We move all terms containing x to the left, all other terms to the right

-3x=6

x=6/-3

x=-2

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