4(2x-7)=7(4x-5)+3x-20

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Solution for 4(2x-7)=7(4x-5)+3x-20 equation:



4(2x-7)=7(4x-5)+3x-20
We move all terms to the left:
4(2x-7)-(7(4x-5)+3x-20)=0
We multiply parentheses
8x-(7(4x-5)+3x-20)-28=0
We calculate terms in parentheses: -(7(4x-5)+3x-20), so:
7(4x-5)+3x-20
We add all the numbers together, and all the variables
3x+7(4x-5)-20
We multiply parentheses
3x+28x-35-20
We add all the numbers together, and all the variables
31x-55
Back to the equation:
-(31x-55)
We get rid of parentheses
8x-31x+55-28=0
We add all the numbers together, and all the variables
-23x+27=0
We move all terms containing x to the left, all other terms to the right
-23x=-27
x=-27/-23
x=1+4/23

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