4(2x-8)+16=-40

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Solution for 4(2x-8)+16=-40 equation: 



4(2x-8)+16=-40

We move all terms to the left:

4(2x-8)+16-(-40)=0

We add all the numbers together, and all the variables

4(2x-8)+56=0

We multiply parentheses

8x-32+56=0

We add all the numbers together, and all the variables

8x+24=0

We move all terms containing x to the left, all other terms to the right

8x=-24

x=-24/8

x=-3

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