4(2x-8)+16=-40

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Solution for 4(2x-8)+16=-40 equation:



4(2x-8)+16=-40
We move all terms to the left:
4(2x-8)+16-(-40)=0
We add all the numbers together, and all the variables
4(2x-8)+56=0
We multiply parentheses
8x-32+56=0
We add all the numbers together, and all the variables
8x+24=0
We move all terms containing x to the left, all other terms to the right
8x=-24
x=-24/8
x=-3

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