4(2x-8)+2(x-4)=5(10-x)

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Solution for 4(2x-8)+2(x-4)=5(10-x) equation: 



4(2x-8)+2(x-4)=5(10-x)

We move all terms to the left:

4(2x-8)+2(x-4)-(5(10-x))=0

We add all the numbers together, and all the variables

4(2x-8)+2(x-4)-(5(-1x+10))=0

We multiply parentheses

8x+2x-(5(-1x+10))-32-8=0



We calculate terms in parentheses: -(5(-1x+10)), so:

5(-1x+10)

We multiply parentheses

-5x+50

Back to the equation:

-(-5x+50)



We add all the numbers together, and all the variables

10x-(-5x+50)-40=0

We get rid of parentheses

10x+5x-50-40=0

We add all the numbers together, and all the variables

15x-90=0

We move all terms containing x to the left, all other terms to the right

15x=90

x=90/15

x=6

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