4(2x-8)=1/7(49x+70)+2

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Solution for 4(2x-8)=1/7(49x+70)+2 equation: 



4(2x-8)=1/7(49x+70)+2

We move all terms to the left:

4(2x-8)-(1/7(49x+70)+2)=0



Domain of the equation: 7(49x+70)+2)!=0

x∈R



We multiply parentheses

8x-(1/7(49x+70)+2)-32=0

We multiply all the terms by the denominator


8x*7(49x+70)-32*7(49x+70)+2)-(1+2)=0

We add all the numbers together, and all the variables

8x*7(49x+70)-32*7(49x+70)+2)-3=0

We add all the numbers together, and all the variables

8x*7(49x+70)-32*7(49x+70)=0

Wy multiply elements

56x^2(4-224x(4=0

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