4(2x-9)-5=4(x-5)+15

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Solution for 4(2x-9)-5=4(x-5)+15 equation: 



4(2x-9)-5=4(x-5)+15

We move all terms to the left:

4(2x-9)-5-(4(x-5)+15)=0

We multiply parentheses

8x-(4(x-5)+15)-36-5=0



We calculate terms in parentheses: -(4(x-5)+15), so:

4(x-5)+15

We multiply parentheses

4x-20+15

We add all the numbers together, and all the variables

4x-5

Back to the equation:

-(4x-5)



We add all the numbers together, and all the variables

8x-(4x-5)-41=0

We get rid of parentheses

8x-4x+5-41=0

We add all the numbers together, and all the variables

4x-36=0

We move all terms containing x to the left, all other terms to the right

4x=36

x=36/4

x=9

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