4(2x2)=-2(3x+16)

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Solution for 4(2x2)=-2(3x+16) equation: 



4(2x^2)=-2(3x+16)

We move all terms to the left:

4(2x^2)-(-2(3x+16))=0



We calculate terms in parentheses: -(-2(3x+16)), so:

-2(3x+16)

We multiply parentheses

-6x-32

Back to the equation:

-(-6x-32)



We get rid of parentheses

42x^2+6x+32=0

a = 42; b = 6; c = +32;
Δ = b2-4ac
Δ = 62-4·42·32
Δ = -5340
Delta is less than zero, so there is no solution for the equation

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