4(2y+1)+3(1+4y)=20

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Solution for 4(2y+1)+3(1+4y)=20 equation: 



4(2y+1)+3(1+4y)=20

We move all terms to the left:

4(2y+1)+3(1+4y)-(20)=0

We add all the numbers together, and all the variables

4(2y+1)+3(4y+1)-20=0

We multiply parentheses

8y+12y+4+3-20=0

We add all the numbers together, and all the variables

20y-13=0

We move all terms containing y to the left, all other terms to the right

20y=13

y=13/20

y=13/20

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