4(2y+1)+3(y+2)=15

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Solution for 4(2y+1)+3(y+2)=15 equation: 


Simplifying
4(2y + 1) + 3(y + 2) = 15

Reorder the terms:
4(1 + 2y) + 3(y + 2) = 15
(1 * 4 + 2y * 4) + 3(y + 2) = 15
(4 + 8y) + 3(y + 2) = 15

Reorder the terms:
4 + 8y + 3(2 + y) = 15
4 + 8y + (2 * 3 + y * 3) = 15
4 + 8y + (6 + 3y) = 15

Reorder the terms:
4 + 6 + 8y + 3y = 15

Combine like terms: 4 + 6 = 10
10 + 8y + 3y = 15

Combine like terms: 8y + 3y = 11y
10 + 11y = 15

Solving
10 + 11y = 15

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 11y = 15 + -10

Combine like terms: 10 + -10 = 0
0 + 11y = 15 + -10
11y = 15 + -10

Combine like terms: 15 + -10 = 5
11y = 5

Divide each side by '11'.
y = 0.4545454545

Simplifying
y = 0.4545454545

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