4(2y+1)+6=2(5y+1)+5

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Solution for 4(2y+1)+6=2(5y+1)+5 equation: 



4(2y+1)+6=2(5y+1)+5

We move all terms to the left:

4(2y+1)+6-(2(5y+1)+5)=0

We multiply parentheses

8y-(2(5y+1)+5)+4+6=0



We calculate terms in parentheses: -(2(5y+1)+5), so:

2(5y+1)+5

We multiply parentheses

10y+2+5

We add all the numbers together, and all the variables

10y+7

Back to the equation:

-(10y+7)



We add all the numbers together, and all the variables

8y-(10y+7)+10=0

We get rid of parentheses

8y-10y-7+10=0

We add all the numbers together, and all the variables

-2y+3=0

We move all terms containing y to the left, all other terms to the right

-2y=-3

y=-3/-2

y=1+1/2

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