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4(2y+1)-3=(y-1)-2
We move all terms to the left:
4(2y+1)-3-((y-1)-2)=0
We multiply parentheses
8y-((y-1)-2)+4-3=0
We calculate terms in parentheses: -((y-1)-2), so:We add all the numbers together, and all the variables
(y-1)-2
We get rid of parentheses
y-1-2
We add all the numbers together, and all the variables
y-3
Back to the equation:
-(y-3)
8y-(y-3)+1=0
We get rid of parentheses
8y-y+3+1=0
We add all the numbers together, and all the variables
7y+4=0
We move all terms containing y to the left, all other terms to the right
7y=-4
y=-4/7
y=-4/7
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