4(2y+1)-3=(y-1)-2

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Solution for 4(2y+1)-3=(y-1)-2 equation: 



4(2y+1)-3=(y-1)-2

We move all terms to the left:

4(2y+1)-3-((y-1)-2)=0

We multiply parentheses

8y-((y-1)-2)+4-3=0



We calculate terms in parentheses: -((y-1)-2), so:

(y-1)-2

We get rid of parentheses

y-1-2

We add all the numbers together, and all the variables

y-3

Back to the equation:

-(y-3)



We add all the numbers together, and all the variables

8y-(y-3)+1=0

We get rid of parentheses

8y-y+3+1=0

We add all the numbers together, and all the variables

7y+4=0

We move all terms containing y to the left, all other terms to the right

7y=-4

y=-4/7

y=-4/7

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