4(2y+1)-3=3(y-1)-2

Solution for 4(2y+1)-3=3(y-1)-2 equation:

4(2y+1)-3=3(y-1)-2

We move all terms to the left:

4(2y+1)-3-(3(y-1)-2)=0

We multiply parentheses

8y-(3(y-1)-2)+4-3=0


We calculate terms in parentheses: -(3(y-1)-2), so:

3(y-1)-2

We multiply parentheses

3y-3-2

We add all the numbers together, and all the variables

3y-5

Back to the equation:

-(3y-5)


We add all the numbers together, and all the variables

8y-(3y-5)+1=0

We get rid of parentheses

8y-3y+5+1=0

We add all the numbers together, and all the variables

5y+6=0

We move all terms containing y to the left, all other terms to the right

5y=-6

y=-6/5

y=-1+1/5