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4(2y+1)=2(3y+5)
We move all terms to the left:
4(2y+1)-(2(3y+5))=0
We multiply parentheses
8y-(2(3y+5))+4=0
We calculate terms in parentheses: -(2(3y+5)), so:We get rid of parentheses
2(3y+5)
We multiply parentheses
6y+10
Back to the equation:
-(6y+10)
8y-6y-10+4=0
We add all the numbers together, and all the variables
2y-6=0
We move all terms containing y to the left, all other terms to the right
2y=6
y=6/2
y=3
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