4(2y+1)=3(12-y)

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Solution for 4(2y+1)=3(12-y) equation: 



4(2y+1)=3(12-y)

We move all terms to the left:

4(2y+1)-(3(12-y))=0

We add all the numbers together, and all the variables

4(2y+1)-(3(-1y+12))=0

We multiply parentheses

8y-(3(-1y+12))+4=0



We calculate terms in parentheses: -(3(-1y+12)), so:

3(-1y+12)

We multiply parentheses

-3y+36

Back to the equation:

-(-3y+36)



We get rid of parentheses

8y+3y-36+4=0

We add all the numbers together, and all the variables

11y-32=0

We move all terms containing y to the left, all other terms to the right

11y=32

y=32/11

y=2+10/11

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