4(2y+1)=3(5y-1)

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Solution for 4(2y+1)=3(5y-1) equation: 



4(2y+1)=3(5y-1)

We move all terms to the left:

4(2y+1)-(3(5y-1))=0

We multiply parentheses

8y-(3(5y-1))+4=0



We calculate terms in parentheses: -(3(5y-1)), so:

3(5y-1)

We multiply parentheses

15y-3

Back to the equation:

-(15y-3)



We get rid of parentheses

8y-15y+3+4=0

We add all the numbers together, and all the variables

-7y+7=0

We move all terms containing y to the left, all other terms to the right

-7y=-7

y=-7/-7

y=1

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