4(2y+10)=2(y-13)

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Solution for 4(2y+10)=2(y-13) equation: 



4(2y+10)=2(y-13)

We move all terms to the left:

4(2y+10)-(2(y-13))=0

We multiply parentheses

8y-(2(y-13))+40=0



We calculate terms in parentheses: -(2(y-13)), so:

2(y-13)

We multiply parentheses

2y-26

Back to the equation:

-(2y-26)



We get rid of parentheses

8y-2y+26+40=0

We add all the numbers together, and all the variables

6y+66=0

We move all terms containing y to the left, all other terms to the right

6y=-66

y=-66/6

y=-11

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