4(2y+10)=2(y-13)

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Solution for 4(2y+10)=2(y-13) equation:



4(2y+10)=2(y-13)
We move all terms to the left:
4(2y+10)-(2(y-13))=0
We multiply parentheses
8y-(2(y-13))+40=0
We calculate terms in parentheses: -(2(y-13)), so:
2(y-13)
We multiply parentheses
2y-26
Back to the equation:
-(2y-26)
We get rid of parentheses
8y-2y+26+40=0
We add all the numbers together, and all the variables
6y+66=0
We move all terms containing y to the left, all other terms to the right
6y=-66
y=-66/6
y=-11

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