4(2y+2)+8=3(3y-1)-2

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Solution for 4(2y+2)+8=3(3y-1)-2 equation: 



4(2y+2)+8=3(3y-1)-2

We move all terms to the left:

4(2y+2)+8-(3(3y-1)-2)=0

We multiply parentheses

8y-(3(3y-1)-2)+8+8=0



We calculate terms in parentheses: -(3(3y-1)-2), so:

3(3y-1)-2

We multiply parentheses

9y-3-2

We add all the numbers together, and all the variables

9y-5

Back to the equation:

-(9y-5)



We add all the numbers together, and all the variables

8y-(9y-5)+16=0

We get rid of parentheses

8y-9y+5+16=0

We add all the numbers together, and all the variables

-1y+21=0

We move all terms containing y to the left, all other terms to the right

-y=-21

y=-21/-1

y=+21

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