4(2y+2)-13=2(5y-4)+15

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Solution for 4(2y+2)-13=2(5y-4)+15 equation: 



4(2y+2)-13=2(5y-4)+15

We move all terms to the left:

4(2y+2)-13-(2(5y-4)+15)=0

We multiply parentheses

8y-(2(5y-4)+15)+8-13=0



We calculate terms in parentheses: -(2(5y-4)+15), so:

2(5y-4)+15

We multiply parentheses

10y-8+15

We add all the numbers together, and all the variables

10y+7

Back to the equation:

-(10y+7)



We add all the numbers together, and all the variables

8y-(10y+7)-5=0

We get rid of parentheses

8y-10y-7-5=0

We add all the numbers together, and all the variables

-2y-12=0

We move all terms containing y to the left, all other terms to the right

-2y=12

y=12/-2

y=-6

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