4(2y+2)-3(4y+1)=5(4y-7)

Solution for 4(2y+2)-3(4y+1)=5(4y-7) equation:

4(2y+2)-3(4y+1)=5(4y-7)

We move all terms to the left:

4(2y+2)-3(4y+1)-(5(4y-7))=0

We multiply parentheses

8y-12y-(5(4y-7))+8-3=0


We calculate terms in parentheses: -(5(4y-7)), so:

5(4y-7)

We multiply parentheses

20y-35

Back to the equation:

-(20y-35)


We add all the numbers together, and all the variables

-4y-(20y-35)+5=0

We get rid of parentheses

-4y-20y+35+5=0

We add all the numbers together, and all the variables

-24y+40=0

We move all terms containing y to the left, all other terms to the right

-24y=-40

y=-40/-24

y=1+2/3