4(2y+3)+3y+2=80

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Solution for 4(2y+3)+3y+2=80 equation: 



4(2y+3)+3y+2=80

We move all terms to the left:

4(2y+3)+3y+2-(80)=0

We add all the numbers together, and all the variables

3y+4(2y+3)-78=0

We multiply parentheses

3y+8y+12-78=0

We add all the numbers together, and all the variables

11y-66=0

We move all terms containing y to the left, all other terms to the right

11y=66

y=66/11

y=6

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