4(2y+3)-3(4y-2)=5(4y-7)

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Solution for 4(2y+3)-3(4y-2)=5(4y-7) equation: 



4(2y+3)-3(4y-2)=5(4y-7)

We move all terms to the left:

4(2y+3)-3(4y-2)-(5(4y-7))=0

We multiply parentheses

8y-12y-(5(4y-7))+12+6=0



We calculate terms in parentheses: -(5(4y-7)), so:

5(4y-7)

We multiply parentheses

20y-35

Back to the equation:

-(20y-35)



We add all the numbers together, and all the variables

-4y-(20y-35)+18=0

We get rid of parentheses

-4y-20y+35+18=0

We add all the numbers together, and all the variables

-24y+53=0

We move all terms containing y to the left, all other terms to the right

-24y=-53

y=-53/-24

y=2+5/24

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