4(2y+3)=5(3y-2)

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Solution for 4(2y+3)=5(3y-2) equation: 



4(2y+3)=5(3y-2)

We move all terms to the left:

4(2y+3)-(5(3y-2))=0

We multiply parentheses

8y-(5(3y-2))+12=0



We calculate terms in parentheses: -(5(3y-2)), so:

5(3y-2)

We multiply parentheses

15y-10

Back to the equation:

-(15y-10)



We get rid of parentheses

8y-15y+10+12=0

We add all the numbers together, and all the variables

-7y+22=0

We move all terms containing y to the left, all other terms to the right

-7y=-22

y=-22/-7

y=3+1/7

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