4(2y+3+6y)=32y+12

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Solution for 4(2y+3+6y)=32y+12 equation: 


Simplifying
4(2y + 3 + 6y) = 32y + 12

Reorder the terms:
4(3 + 2y + 6y) = 32y + 12

Combine like terms: 2y + 6y = 8y
4(3 + 8y) = 32y + 12
(3 * 4 + 8y * 4) = 32y + 12
(12 + 32y) = 32y + 12

Reorder the terms:
12 + 32y = 12 + 32y

Add '-12' to each side of the equation.
12 + -12 + 32y = 12 + -12 + 32y

Combine like terms: 12 + -12 = 0
0 + 32y = 12 + -12 + 32y
32y = 12 + -12 + 32y

Combine like terms: 12 + -12 = 0
32y = 0 + 32y
32y = 32y

Add '-32y' to each side of the equation.
32y + -32y = 32y + -32y

Combine like terms: 32y + -32y = 0
0 = 32y + -32y

Combine like terms: 32y + -32y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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