4(2y+4)-5=27

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Solution for 4(2y+4)-5=27 equation: 



4(2y+4)-5=27

We move all terms to the left:

4(2y+4)-5-(27)=0

We add all the numbers together, and all the variables

4(2y+4)-32=0

We multiply parentheses

8y+16-32=0

We add all the numbers together, and all the variables

8y-16=0

We move all terms containing y to the left, all other terms to the right

8y=16

y=16/8

y=2

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