4(2y+5)-3(y-8)=2(y-3)

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Solution for 4(2y+5)-3(y-8)=2(y-3) equation:



4(2y+5)-3(y-8)=2(y-3)
We move all terms to the left:
4(2y+5)-3(y-8)-(2(y-3))=0
We multiply parentheses
8y-3y-(2(y-3))+20+24=0
We calculate terms in parentheses: -(2(y-3)), so:
2(y-3)
We multiply parentheses
2y-6
Back to the equation:
-(2y-6)
We add all the numbers together, and all the variables
5y-(2y-6)+44=0
We get rid of parentheses
5y-2y+6+44=0
We add all the numbers together, and all the variables
3y+50=0
We move all terms containing y to the left, all other terms to the right
3y=-50
y=-50/3
y=-16+2/3

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