4(2y+5/3)-5y=142

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Solution for 4(2y+5/3)-5y=142 equation: 


y in (-oo:+oo)

4*(2*y+5/3)-(5*y) = 142 // - 142

4*(2*y+5/3)-(5*y)-142 = 0

4*(2*y+5/3)-5*y-142 = 0

4*(2*y+5/3)-5*y-142 = 0

3*y-142+20/3 = 0

3*y-406/3 = 0

3*y-406/3 = 0

3*y-406/3 = 0 // + 406/3

3*y = 406/3 // : 3

y = 406/3/3

y = 406/9

y = 406/9

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