4(2y-)=64+12y

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Solution for 4(2y-)=64+12y equation: 



4(2y-)=64+12y

We move all terms to the left:

4(2y-)-(64+12y)=0

We add all the numbers together, and all the variables

4(+2y)-(12y+64)=0

We multiply parentheses

8y-(12y+64)=0

We get rid of parentheses

8y-12y-64=0

We add all the numbers together, and all the variables

-4y-64=0

We move all terms containing y to the left, all other terms to the right

-4y=64

y=64/-4

y=-16

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