4(2y-1)+11=2(3y-2)-17

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Solution for 4(2y-1)+11=2(3y-2)-17 equation: 



4(2y-1)+11=2(3y-2)-17

We move all terms to the left:

4(2y-1)+11-(2(3y-2)-17)=0

We multiply parentheses

8y-(2(3y-2)-17)-4+11=0



We calculate terms in parentheses: -(2(3y-2)-17), so:

2(3y-2)-17

We multiply parentheses

6y-4-17

We add all the numbers together, and all the variables

6y-21

Back to the equation:

-(6y-21)



We add all the numbers together, and all the variables

8y-(6y-21)+7=0

We get rid of parentheses

8y-6y+21+7=0

We add all the numbers together, and all the variables

2y+28=0

We move all terms containing y to the left, all other terms to the right

2y=-28

y=-28/2

y=-14

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