4(2y-1)+3y=40

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Solution for 4(2y-1)+3y=40 equation: 



4(2y-1)+3y=40

We move all terms to the left:

4(2y-1)+3y-(40)=0

We add all the numbers together, and all the variables

3y+4(2y-1)-40=0

We multiply parentheses

3y+8y-4-40=0

We add all the numbers together, and all the variables

11y-44=0

We move all terms containing y to the left, all other terms to the right

11y=44

y=44/11

y=4

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