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4(2y-1)-1/2y=1/2(5-3y)
We move all terms to the left:
4(2y-1)-1/2y-(1/2(5-3y))=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 2(5-3y))!=0We add all the numbers together, and all the variables
y∈R
4(2y-1)-1/2y-(1/2(-3y+5))=0
We multiply parentheses
8y-1/2y-(1/2(-3y+5))-4=0
We calculate fractions
8y+(-2y(-)/(4y^2(-)+(-(1*2y)/(4y^2(-)-4=0
We can not solve this equation
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