4(2y-1)=-8(0.50-y)

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Solution for 4(2y-1)=-8(0.50-y) equation:


Simplifying
4(2y + -1) = -8(0.50 + -1y)

Reorder the terms:
4(-1 + 2y) = -8(0.50 + -1y)
(-1 * 4 + 2y * 4) = -8(0.50 + -1y)
(-4 + 8y) = -8(0.50 + -1y)
-4 + 8y = (0.50 * -8 + -1y * -8)
-4 + 8y = (-4 + 8y)

Add '4' to each side of the equation.
-4 + 4 + 8y = -4 + 4 + 8y

Combine like terms: -4 + 4 = 0
0 + 8y = -4 + 4 + 8y
8y = -4 + 4 + 8y

Combine like terms: -4 + 4 = 0
8y = 0 + 8y
8y = 8y

Add '-8y' to each side of the equation.
8y + -8y = 8y + -8y

Combine like terms: 8y + -8y = 0
0 = 8y + -8y

Combine like terms: 8y + -8y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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