4(2y-1)=-8(1/2-y)

Solution for 4(2y-1)=-8(1/2-y) equation:

4(2y-1)=-8(1/2-y)

We move all terms to the left:

4(2y-1)-(-8(1/2-y))=0


Domain of the equation: 2-y))!=0

We move all terms containing y to the left, all other terms to the right

-y))!=-2

y!=-2/1

y!=-2

y∈R


We add all the numbers together, and all the variables

4(2y-1)-(-8(-1y+1/2))=0

We multiply parentheses

8y-(-8(-1y+1/2))-4=0

We multiply all the terms by the denominator


8y*2))-(-8(-1y+1-4*2))=0

We add all the numbers together, and all the variables

8y*2))-(-8(-1y-7))=0

We add all the numbers together, and all the variables

-1y+8y*2))-(-8(=0

Wy multiply elements

16y^2-1y=0

a = 16; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·16·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*16}=\frac{0}{32}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*16}=\frac{2}{32}
=1/16
$