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4(2y-1)=2(y+4)
We move all terms to the left:
4(2y-1)-(2(y+4))=0
We multiply parentheses
8y-(2(y+4))-4=0
We calculate terms in parentheses: -(2(y+4)), so:We get rid of parentheses
2(y+4)
We multiply parentheses
2y+8
Back to the equation:
-(2y+8)
8y-2y-8-4=0
We add all the numbers together, and all the variables
6y-12=0
We move all terms containing y to the left, all other terms to the right
6y=12
y=12/6
y=2
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