4(2y-10)+5y=38

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Solution for 4(2y-10)+5y=38 equation: 



4(2y-10)+5y=38

We move all terms to the left:

4(2y-10)+5y-(38)=0

We add all the numbers together, and all the variables

5y+4(2y-10)-38=0

We multiply parentheses

5y+8y-40-38=0

We add all the numbers together, and all the variables

13y-78=0

We move all terms containing y to the left, all other terms to the right

13y=78

y=78/13

y=6

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