4(2y-12)+28=8y-20

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Solution for 4(2y-12)+28=8y-20 equation:


Simplifying
4(2y + -12) + 28 = 8y + -20

Reorder the terms:
4(-12 + 2y) + 28 = 8y + -20
(-12 * 4 + 2y * 4) + 28 = 8y + -20
(-48 + 8y) + 28 = 8y + -20

Reorder the terms:
-48 + 28 + 8y = 8y + -20

Combine like terms: -48 + 28 = -20
-20 + 8y = 8y + -20

Reorder the terms:
-20 + 8y = -20 + 8y

Add '20' to each side of the equation.
-20 + 20 + 8y = -20 + 20 + 8y

Combine like terms: -20 + 20 = 0
0 + 8y = -20 + 20 + 8y
8y = -20 + 20 + 8y

Combine like terms: -20 + 20 = 0
8y = 0 + 8y
8y = 8y

Add '-8y' to each side of the equation.
8y + -8y = 8y + -8y

Combine like terms: 8y + -8y = 0
0 = 8y + -8y

Combine like terms: 8y + -8y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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