4(2y-2)+5y=31

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Solution for 4(2y-2)+5y=31 equation: 



4(2y-2)+5y=31

We move all terms to the left:

4(2y-2)+5y-(31)=0

We add all the numbers together, and all the variables

5y+4(2y-2)-31=0

We multiply parentheses

5y+8y-8-31=0

We add all the numbers together, and all the variables

13y-39=0

We move all terms containing y to the left, all other terms to the right

13y=39

y=39/13

y=3

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