4(2y-3)+2(3y+1)=6y+22

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Solution for 4(2y-3)+2(3y+1)=6y+22 equation: 



4(2y-3)+2(3y+1)=6y+22

We move all terms to the left:

4(2y-3)+2(3y+1)-(6y+22)=0

We multiply parentheses

8y+6y-(6y+22)-12+2=0

We get rid of parentheses

8y+6y-6y-22-12+2=0

We add all the numbers together, and all the variables

8y-32=0

We move all terms containing y to the left, all other terms to the right

8y=32

y=32/8

y=4

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