4(2y-3)+2(y+1)=7y-3

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Solution for 4(2y-3)+2(y+1)=7y-3 equation: 



4(2y-3)+2(y+1)=7y-3

We move all terms to the left:

4(2y-3)+2(y+1)-(7y-3)=0

We multiply parentheses

8y+2y-(7y-3)-12+2=0

We get rid of parentheses

8y+2y-7y+3-12+2=0

We add all the numbers together, and all the variables

3y-7=0

We move all terms containing y to the left, all other terms to the right

3y=7

y=7/3

y=2+1/3

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