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4(2y-3)+2(y+1)=7y-3
We move all terms to the left:
4(2y-3)+2(y+1)-(7y-3)=0
We multiply parentheses
8y+2y-(7y-3)-12+2=0
We get rid of parentheses
8y+2y-7y+3-12+2=0
We add all the numbers together, and all the variables
3y-7=0
We move all terms containing y to the left, all other terms to the right
3y=7
y=7/3
y=2+1/3
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