4(2y-3)+5(y-5)=6(y+12)

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Solution for 4(2y-3)+5(y-5)=6(y+12) equation: 



4(2y-3)+5(y-5)=6(y+12)

We move all terms to the left:

4(2y-3)+5(y-5)-(6(y+12))=0

We multiply parentheses

8y+5y-(6(y+12))-12-25=0



We calculate terms in parentheses: -(6(y+12)), so:

6(y+12)

We multiply parentheses

6y+72

Back to the equation:

-(6y+72)



We add all the numbers together, and all the variables

13y-(6y+72)-37=0

We get rid of parentheses

13y-6y-72-37=0

We add all the numbers together, and all the variables

7y-109=0

We move all terms containing y to the left, all other terms to the right

7y=109

y=109/7

y=15+4/7

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