4(2y-3)=-4y+4+8y

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Solution for 4(2y-3)=-4y+4+8y equation: 



4(2y-3)=-4y+4+8y

We move all terms to the left:

4(2y-3)-(-4y+4+8y)=0

We add all the numbers together, and all the variables

4(2y-3)-(4y+4)=0

We multiply parentheses

8y-(4y+4)-12=0

We get rid of parentheses

8y-4y-4-12=0

We add all the numbers together, and all the variables

4y-16=0

We move all terms containing y to the left, all other terms to the right

4y=16

y=16/4

y=4

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