4(2y-3)=8y-12

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Solution for 4(2y-3)=8y-12 equation:



4(2y-3)=8y-12
We move all terms to the left:
4(2y-3)-(8y-12)=0
We multiply parentheses
8y-(8y-12)-12=0
We get rid of parentheses
8y-8y+12-12=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0

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