4(2y-3)=8y-12

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Solution for 4(2y-3)=8y-12 equation: 



4(2y-3)=8y-12

We move all terms to the left:

4(2y-3)-(8y-12)=0

We multiply parentheses

8y-(8y-12)-12=0

We get rid of parentheses

8y-8y+12-12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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