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4(2y-5)+3=-9-(3y+4)
We move all terms to the left:
4(2y-5)+3-(-9-(3y+4))=0
We multiply parentheses
8y-(-9-(3y+4))-20+3=0
We calculate terms in parentheses: -(-9-(3y+4)), so:We add all the numbers together, and all the variables
-9-(3y+4)
determiningTheFunctionDomain -(3y+4)-9
We get rid of parentheses
-3y-4-9
We add all the numbers together, and all the variables
-3y-13
Back to the equation:
-(-3y-13)
8y-(-3y-13)-17=0
We get rid of parentheses
8y+3y+13-17=0
We add all the numbers together, and all the variables
11y-4=0
We move all terms containing y to the left, all other terms to the right
11y=4
y=4/11
y=4/11
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