4(2y-5)=-18-2(-4y+1)

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Solution for 4(2y-5)=-18-2(-4y+1) equation:



4(2y-5)=-18-2(-4y+1)
We move all terms to the left:
4(2y-5)-(-18-2(-4y+1))=0
We multiply parentheses
8y-(-18-2(-4y+1))-20=0
We calculate terms in parentheses: -(-18-2(-4y+1)), so:
-18-2(-4y+1)
determiningTheFunctionDomain -2(-4y+1)-18
We multiply parentheses
8y-2-18
We add all the numbers together, and all the variables
8y-20
Back to the equation:
-(8y-20)
We get rid of parentheses
8y-8y+20-20=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0

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