4(2y-5)=-18-2(-4y+1)

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Solution for 4(2y-5)=-18-2(-4y+1) equation: 



4(2y-5)=-18-2(-4y+1)

We move all terms to the left:

4(2y-5)-(-18-2(-4y+1))=0

We multiply parentheses

8y-(-18-2(-4y+1))-20=0



We calculate terms in parentheses: -(-18-2(-4y+1)), so:

-18-2(-4y+1)

determiningTheFunctionDomain
-2(-4y+1)-18

We multiply parentheses

8y-2-18

We add all the numbers together, and all the variables

8y-20

Back to the equation:

-(8y-20)



We get rid of parentheses

8y-8y+20-20=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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