4(2y-5)=35

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Solution for 4(2y-5)=35 equation: 



4(2y-5)=35

We move all terms to the left:

4(2y-5)-(35)=0

We multiply parentheses

8y-20-35=0

We add all the numbers together, and all the variables

8y-55=0

We move all terms containing y to the left, all other terms to the right

8y=55

y=55/8

y=6+7/8

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