4(2y-5)=5(y-2)

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Solution for 4(2y-5)=5(y-2) equation: 



4(2y-5)=5(y-2)

We move all terms to the left:

4(2y-5)-(5(y-2))=0

We multiply parentheses

8y-(5(y-2))-20=0



We calculate terms in parentheses: -(5(y-2)), so:

5(y-2)

We multiply parentheses

5y-10

Back to the equation:

-(5y-10)



We get rid of parentheses

8y-5y+10-20=0

We add all the numbers together, and all the variables

3y-10=0

We move all terms containing y to the left, all other terms to the right

3y=10

y=10/3

y=3+1/3

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