4(2y-6)=32-8

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Solution for 4(2y-6)=32-8 equation: 



4(2y-6)=32-8

We move all terms to the left:

4(2y-6)-(32-8)=0

We add all the numbers together, and all the variables

4(2y-6)-24=0

We multiply parentheses

8y-24-24=0

We add all the numbers together, and all the variables

8y-48=0

We move all terms containing y to the left, all other terms to the right

8y=48

y=48/8

y=6

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