4(2y-7)=6412y

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Solution for 4(2y-7)=6412y equation: 



4(2y-7)=6412y

We move all terms to the left:

4(2y-7)-(6412y)=0

We add all the numbers together, and all the variables

-6412y+4(2y-7)=0

We multiply parentheses

-6412y+8y-28=0

We add all the numbers together, and all the variables

-6404y-28=0

We move all terms containing y to the left, all other terms to the right

-6404y=28

y=28/-6404

y=-7/1601

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