4(2y-8)-y=-2(y-4)

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Solution for 4(2y-8)-y=-2(y-4) equation: 



4(2y-8)-y=-2(y-4)

We move all terms to the left:

4(2y-8)-y-(-2(y-4))=0

We add all the numbers together, and all the variables

-1y+4(2y-8)-(-2(y-4))=0

We multiply parentheses

-1y+8y-(-2(y-4))-32=0



We calculate terms in parentheses: -(-2(y-4)), so:

-2(y-4)

We multiply parentheses

-2y+8

Back to the equation:

-(-2y+8)



We add all the numbers together, and all the variables

7y-(-2y+8)-32=0

We get rid of parentheses

7y+2y-8-32=0

We add all the numbers together, and all the variables

9y-40=0

We move all terms containing y to the left, all other terms to the right

9y=40

y=40/9

y=4+4/9

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