4(2y-y)=64+12y

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Solution for 4(2y-y)=64+12y equation:



4(2y-y)=64+12y
We move all terms to the left:
4(2y-y)-(64+12y)=0
We add all the numbers together, and all the variables
4(+y)-(12y+64)=0
We multiply parentheses
4y-(12y+64)=0
We get rid of parentheses
4y-12y-64=0
We add all the numbers together, and all the variables
-8y-64=0
We move all terms containing y to the left, all other terms to the right
-8y=64
y=64/-8
y=-8

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