4(2z+1)-3(z-8)=15+6z

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Solution for 4(2z+1)-3(z-8)=15+6z equation: 



4(2z+1)-3(z-8)=15+6z

We move all terms to the left:

4(2z+1)-3(z-8)-(15+6z)=0

We add all the numbers together, and all the variables

4(2z+1)-3(z-8)-(6z+15)=0

We multiply parentheses

8z-3z-(6z+15)+4+24=0

We get rid of parentheses

8z-3z-6z-15+4+24=0

We add all the numbers together, and all the variables

-1z+13=0

We move all terms containing z to the left, all other terms to the right

-z=-13

z=-13/-1

z=+13

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